Which one of the following reactions of alkenes does the Anti-Markovnikov’s rule apply instead of Markovnikov’s rule?
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Correct Answer: C. Hydroboration-oxidation
The electronegativity of the hydrogen atom is stronger than that of boron, which means hydrogen is relatively negatively charged compared to boron. So in this case, the hydrogen will be added to the end containing more substituents and the boron part will be added to the end containing more hydrogen atoms, which will then convert to the hydroxyl group. This is the Anti-Markovnikov product.
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