A 1 mol sample of ammonia gas (NH3) at 1 atm and 273 K is compressed to 2 atm. What is the difference in volume before and after compression?
Loading ...
Correct Answer: C. 11.2 L
This is solved using the ideal gas law. However, it should be recognized that 1 mol of any gas at 1 atm and 273K (or 0 deg Celsius) is approximately 22.4 L in volume. If this is not recognized, it can still be calculated from the ideal gas law, PV = nRT. We recognize that if pressure doubles while temperature and mols remain the same, the volume should be halved. Thus, the new volume is 11.2 L, which is a difference of 11.2 liters, or answer C.
Subscribe below to receive the DAT Question of the Day delivered straight to your inbox every morning.
Photo attributed to Rudolf_Schuba.
